feat(insta): dedup_window_days config end-to-end wiring (spec 6.4)

- insta-lab ranked_keywords: add dedup_window_days Query param (default 14, ge=1, le=90); pass to db.list_recent_issued_topics
- service_proxy.insta_ranked: add dedup_window_days param (default 14); include in GET params
- InstaAgent.on_schedule: read dedup_window_days from custom_config (default 14); pass to insta_ranked call
- test_ranked_respects_dedup_window: verifies window param gates eligible flag correctly

Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
This commit is contained in:
2026-06-11 02:55:46 +09:00
parent 149e7c40fe
commit e1b1944f43
4 changed files with 41 additions and 5 deletions

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@@ -45,3 +45,34 @@ def test_decision_invalid_400(client):
def test_decision_unknown_slate_404(client):
r = client.post("/api/insta/slates/99999/decision", json={"decision": "approved"})
assert r.status_code == 404
def test_ranked_respects_dedup_window(client):
"""dedup_window_days param이 list_recent_issued_topics window에 반영되는지 검증.
'금리' 키워드를 방금 approved(published) 상태로 기록한 뒤:
- dedup_window_days=30 → 방금 발행 = window 안 → eligible False
- dedup_window_days=1 → DB datetime이 정각 경계 직전이라도 여전히 1일 안이므로 eligible False
(확인: 반드시 eligible=False)
추가로 두 번째 키워드(word2)는 아직 발행 이력 없으므로 window 무관하게 eligible True.
"""
# 방금 발행된 키워드 등록 + 슬레이트 approved 처리
db.add_trending_keyword({"keyword": "금리", "category": "economy", "score": 0.9})
sid = db.add_card_slate({"keyword": "금리", "category": "economy"})
db.set_slate_decision(sid, "approved") # published_at = now
# 발행 이력 없는 키워드 추가
db.add_trending_keyword({"keyword": "환율", "category": "economy", "score": 0.8})
# window=30 → '금리'는 최근 발행이라 dedup 대상 → eligible False
r = client.get("/api/insta/keywords/ranked?threshold=0.0&limit=10&dedup_window_days=30")
assert r.status_code == 200
items = r.json()["items"]
keumni = next((i for i in items if i["keyword"] == "금리"), None)
assert keumni is not None, "'금리' 항목이 ranked 응답에 없음"
assert keumni["eligible"] is False, "dedup_window_days=30 내 발행 → eligible은 False여야 함"
# 발행 이력 없는 '환율'은 어떤 window에서도 eligible True
hwanul = next((i for i in items if i["keyword"] == "환율"), None)
assert hwanul is not None, "'환율' 항목이 ranked 응답에 없음"
assert hwanul["eligible"] is True, "발행 이력 없는 키워드는 eligible True여야 함"